21 合并两个有序链表
将两个升序链表合并为一个新的 升序 链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。
示例:
输入:1->2->4, 1->3->4
输出:1->1->2->3->4->4
解法
- Python
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def mergeTwoLists(self, l1: ListNode, l2: ListNode) -> ListNode:
dummy = ListNode(-1)
first = dummy
while l1 and l2:
if l1.val >= l2.val:
first.next = l2
l2 = l2.next
else:
first.next = l1
l1 = l1.next
first = first.next
while l1:
first.next = l1
l1 = l1.next
first = first.next
while l2:
first.next = l2
l2 = l2.next
first = first.next
return dummy.next
- C++
class Solution {
public:
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
ListNode* dummy = new ListNode(-1);
ListNode* first = dummy;
while (l1&&l2){
if (l1->val > l2->val){
first->next = l2;
l2 = l2->next;
}
else{
first-> next = l1;
l1 = l1->next;
}
first = first->next;
}
while (l1){
first->next = l1;
l1 = l1->next;
first = first->next;
}
while (l2){
first->next = l2;
l2 = l2->next;
first = first->next;
}
return dummy->next;
}
};